Advanced Formula Challenge #2: Results and Discussion 3

Last week I set readers the challenge which can be found here.

Three solutions were offered, two of which from the same person, and both of which were correct! So many congratulations to Bill on successfully solving what was quite a complex challenge!

Indeed, as Ben Schwartz pointed out, this challenge appears to have been set previously on the internet, and seems to have been only partially solved on those occasions. In any case, thanks also to Ben for his suggestion, which he confesses was cobbled together from those previous solutions he found, and which worked in all but a few exceptional cases.

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ROW vs ROWS for consecutive integer generation 6

Often we wish to incorporate into our formula a construction which, as that formula is copied down to successive rows, will generate a series of consecutive integers, usually beginning with 1.

A classic example is the standard INDEX/SMALL set-up for returning multiple values corresponding to a certain set of criteria, e.g.:

=INDEX($B1:$B10,SMALL(IF($A$1:$A$10="A",ROW($A$1:$A$10)-MIN(ROW($A$1:$A$10))+1),1))

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Advanced Formula Challenge #2: Identifying Anagrams 8

For this, the 2nd in the series of Advanced Formula Challenges, readers are asked to come up with a solution to the following:

Identifying Anagrams

Given two lists of names in B1:B10 and E1:E10 (as above), a formula is to be entered into A1, such that, when copied down to A10, returns TRUE if, for the corresponding name in column B, there exists at least one name in the range E1:E10 which is an anagram of that name.

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Advanced Formula Challenge #1: Results and Discussion 4

Last Sunday I set a challenge to readers to come up with a solution to the problem here.

Even though this site’s only been up for one week, I’m quite happy to have received the single solution that I did, even more so since that solution was a correct one, from John Jairo Vergara Domìnguez, whose offering you can see if you scroll down to the bottom of that link. Thanks again, John, and well done!

As excellent as John’s solution was, it would still require a little tweaking to work for other ranges (part of its construction is dependent on the array in question being in certain columns within the worksheet) and, in any case, I would now like to present the solution that I developed for this problem.

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INDEX: Returning entire rows/columns Reply

If either (or sometimes both – see below) of the row or column parameters is zero, or omitted, and the INDEX is properly coerced (e.g. forms part of a larger formula), a reference to the entire specified column or row is generated. Note that the return here is not a single value, but rather an array of values.

We are not so much interested in returning this array in an actual cell somewhere (which in any case we can’t do), but more in being able to reference/manipulate that array in further calculations. For example:

=INDEX(A1:C3,0,2)

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Advanced Formula Challenge #1: Single column from many (containing blanks) (2) – Columns first 2

We saw in a previous post (here) an outline for a solution which, given a two-dimensional array, potentially containing some empty cells, generated a list of all non-blank entries from that array in a single column.

In that solution the returned entries were listed in an order which is consistent with the entries from an entire row from the original array being returned prior to moving onto those in the next row. The converse, in which entries are returned in a columns-first fashion, is the challenge I would like to set for any readers of this post willing to have a go.

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Single column from many (containing blanks) (1) – Rows first 15

Given a two-dimensional array, potentially containing some empty cells, it is sometimes desirable to create a list of all non-blank entries from that array in a single column.

In general, it is not a major concern in which order the returns appear in this new column, and indeed the “standard” solution for this problem is the one given here, in which those returns are listed in an order which is consistent with the entries from an entire row from the original array being returned prior to moving onto those in the next row. The converse, in which entries are returned in a columns-first fashion, will be the subject of my first Advanced Formula Challenge post to follow this one.

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